Here are the answers to your questions based on the information provided:
Question 1:
A) How does stoichiometry support the law of conservation of mass?
Correct Response: It compares the mass of each reactant to the mass of each product.
Question 2:
A) Nitrogen gas and hydrogen gas react to produce ammonia according to the given equation. Which ratio of components is correct?
Correct Response: For every 3 moles of hydrogen gas, the reaction produces 2 moles of ammonia.
Question 3:
A) When the reaction produces 68 grams of ammonia, how many grams of nitrogen were present initially?
To calculate this, first find how many moles of NH3 are produced:
Molar mass of NH3 = 14 (N) + 3(1) (H) = 17 g/mol.
Moles of NH3 produced = 68 g / 17 g/mol = 4 moles.
From the balanced equation, 2 moles of NH3 are produced from 1 mole of N2. Therefore, the amount of N2 required = 4 moles NH3 * (1 mole N2 / 2 moles NH3) = 2 moles N2.
Mass of N2 = 2 moles * 28 g/mol (for N2) = 56 grams.
Correct Response: 56
Question 4:
A) Given the molar mass of A is 8 g/mol and the molar mass of B is 12 g/mol, which option shows the correct molar mass of AB2?
Molar mass of AB2 = Molar mass of A + 2 * Molar mass of B = 8 + 2(12) = 8 + 24 = 32 g/mol.
Correct Response: 32 g/mol
Question 5:
A) When the reaction starts with 64 grams of oxygen and a sufficient quantity of hydrogen, how many moles of water are produced?
First, calculate moles of O2:
Moles of O2 = 64 g / 32 g/mol = 2 moles.
From the balanced equation, 1 mole of O2 produces 2 moles of H2O, so 2 moles of O2 will produce 4 moles of H2O.
Correct Response: 4
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