A force 0.8₦ stretches an elastics spring by3m find the elastic constant of the spring

Answer 1

To find the elastic constant (spring constant) of a spring, you can use Hooke's Law, which states:

\[ F = k \cdot x \]

Where:

• \( F \) is the force applied to the spring (in newtons),
• \( k \) is the spring constant (in newtons per meter),
• \( x \) is the extension (or compression) of the spring (in meters).

In this case, you have:

• \( F = 0.8 , \text{N} \)
• \( x = 3 , \text{m} \)

Rearranging the formula to find \( k \):

\[ k = \frac{F}{x} \]

Substituting the values:

\[ k = \frac{0.8 , \text{N}}{3 , \text{m}} \]

\[ k \approx 0.2667 , \text{N/m} \]

Therefore, the elastic constant (spring constant) of the spring is approximately 0.267 N/m.