To find a table of ordered pairs for the parabola \( y = -14x^2 + 3x - 6 \), we can substitute different values of \( x \) into the equation to calculate the corresponding values of \( y \).
Let's compute some values of \( y \):
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For \( x = -1 \): \[ y = -14(-1)^2 + 3(-1) - 6 = -14(1) - 3 - 6 = -14 - 3 - 6 = -23 \] So, the point is \( (-1, -23) \).
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For \( x = 0 \): \[ y = -14(0)^2 + 3(0) - 6 = -6 \] So, the point is \( (0, -6) \).
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For \( x = 1 \): \[ y = -14(1)^2 + 3(1) - 6 = -14(1) + 3 - 6 = -14 + 3 - 6 = -17 \] So, the point is \( (1, -17) \).
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For \( x = 2 \): \[ y = -14(2)^2 + 3(2) - 6 = -14(4) + 6 - 6 = -56 + 6 - 6 = -56 \] So, the point is \( (2, -56) \).
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For \( x = -2 \): \[ y = -14(-2)^2 + 3(-2) - 6 = -14(4) - 6 - 6 = -56 - 6 - 6 = -68 \] So, the point is \( (-2, -68) \).
Now, we have the following ordered pairs:
- \( (-2, -68) \)
- \( (-1, -23) \)
- \( (0, -6) \)
- \( (1, -17) \)
- \( (2, -56) \)
You can create a table using these values, and you can compare it with the given options to see which one matches these pairs. If you have specific options for tables, please provide them, and I can help you determine which is correct!
1 answer