Question

At 1100 K, Kp = 0.25 for the reaction
2SO2(g) + O2(g) equilibrium with 2SO3(g)
What is the value of Kc at this temperature?

Answer 1

Kc = Kp^{-delta n}

Answer 2

is .25 the right answer? if Kp = to .25 and -delta n is the # of mols in prod - # of mols in reactants then that equals out to 1. please tell me if i messed up somewhere

Answer 3

No. You haven't multiplied by RT but I goofed and didn't put that in my answer.
Kc = Kp(RT)^{-delta n}
Kc = 0.25[0.08205*1100)^-(-1)
You are right that delta n is 2-3 = -1