Asked by Wolf
At 1100 K, Kp = 0.25 for the reaction
2SO2(g) + O2(g) equilibrium with 2SO3(g)
What is the value of Kc at this temperature?
2SO2(g) + O2(g) equilibrium with 2SO3(g)
What is the value of Kc at this temperature?
Answers
Answered by
DrBob222
Kc = Kp<sup>-delta n</sup>
Answered by
Wolf
is .25 the right answer? if Kp = to .25 and -delta n is the # of mols in prod - # of mols in reactants then that equals out to 1. please tell me if i messed up somewhere
Answered by
DrBob222
No. You haven't multiplied by RT but I goofed and didn't put that in my answer.
Kc = Kp(RT)<sup>-delta n</sup>
Kc = 0.25[0.08205*1100)<sup>-(-1)</sup>
You are right that delta n is 2-3 = -1
Kc = Kp(RT)<sup>-delta n</sup>
Kc = 0.25[0.08205*1100)<sup>-(-1)</sup>
You are right that delta n is 2-3 = -1
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