To find the x-intercepts of the function that translates the original function \( f(x) = x^2 \) down 4 units, we first need to determine the equation of the translated function.
When a function \( f(x) \) is translated down by \( k \) units, the new function becomes:
\[ g(x) = f(x) - k \]
In this case, the function is translated down 4 units, so we have:
\[ g(x) = x^2 - 4 \]
To find the x-intercepts, we set \( g(x) \) equal to zero and solve for \( x \):
\[ x^2 - 4 = 0 \]
This can be factored as:
\[ (x - 2)(x + 2) = 0 \]
Setting each factor equal to zero gives us:
\[ x - 2 = 0 \quad \Rightarrow \quad x = 2 \]
\[ x + 2 = 0 \quad \Rightarrow \quad x = -2 \]
Thus, the x-intercepts of the function \( g(x) = x^2 - 4 \) are:
\[ x = -2 \quad \text{and} \quad x = 2 \]
The correct response is:
x = -2 and x = 2.