A seesaw spinner designed for children aged 6–8 years old has 4 seats. The total weight limit for 4 riders is 170 pounds. Four children want to use the seesaw spinner. Three of the four children already weigh a total of 120 pounds. At most, how heavy can the fourth child weigh for the total weight to be within the limit? Write the missing operation and symbol so the inequality will represent the maximum weight of the fourth player. You will find the option to add inequality symbols in the Comparison (<)

Question

keyboard.

Answer 1

To determine the maximum weight the fourth child can weigh while keeping the total weight within the limit, we can set up the inequality.

Let \( x \) be the weight of the fourth child. The total weight of the four children should not exceed 170 pounds. The equation can be formulated as follows:

\[ 120 + x \leq 170 \]

To isolate \( x \), we can subtract 120 from both sides:

\[ x \leq 170 - 120 \]

This simplifies to:

\[ x \leq 50 \]

Thus, the missing operation and symbol in the inequality representing the maximum weight of the fourth child is:

\[ \leq \]

So the complete inequality is:

\[ 120 + x \leq 170 \]

And the maximum weight of the fourth child can be 50 pounds or less.