Let's denote the length of the stick as 1, which corresponds to 10 tenths. We'll denote the lengths of the three pieces as \( x \), \( y \), and \( z \), where \( x \), \( y \), and \( z \) are all different and must satisfy the following constraints:
- \( x + y + z = 10 \) (since the total length of the stick is 10 tenths)
- \( x, y, z \) are all different.
- \( x, y, z \geq 1 \) (since they are in tenths, the smallest piece can be 1 tenth).
Here are three different ways in which Christopher could break the stick into three pieces:
Example 1:
- \( x = 1 \)
- \( y = 3 \)
- \( z = 6 \)
Equation: \( 1 + 3 + 6 = 10 \)
Example 2:
- \( x = 2 \)
- \( y = 4 \)
- \( z = 4 \) (not valid since two pieces are of the same length)
But to keep it valid, let's consider:
- \( x = 2 \)
- \( y = 3 \)
- \( z = 5 \)
Equation: \( 2 + 3 + 5 = 10 \)
Example 3:
- \( x = 1 \)
- \( y = 4 \)
- \( z = 5 \)
Equation: \( 1 + 4 + 5 = 10 \)
To summarize, here are the valid equations showing Christopher's different ways to break the stick:
- \( 1 + 3 + 6 = 10 \)
- \( 2 + 3 + 5 = 10 \)
- \( 1 + 4 + 5 = 10 \)