Coulomb's Law PhET Simulation: Investigation of How Magnitude (size) of Charge Affects Electrostatic Force Part 1

For this part, we will be adjusting the size of CHARGE 1 ONLY.
Set the distance between the two charges for 4 cm
Set charge 2 for 8 µC
Given the charge values and the distances, determine the electrostatic force between the charged particles and if they are attracted, repelled, or neither. (**Remember, like charges repel and opposite charges attract)

Column A
1.
Trial 1: Force =:
Trial 1: Force =
2.
Trial 2: Force =:
Trial 2: Force =
3.
Trial 3: Force =:
Trial 3: Force =
4.
Trial 4: Force =:
Trial 4: Force =
5.
Trial 1: Are the two charge ions attracted, repelled, or neither?:
Trial 1: Are the two charge ions attracted, repelled, or neither?
6.
Trial 2: Are the two charge ions attracted, repelled, or neither?:
Trial 2: Are the two charge ions attracted, repelled, or neither?
7.
Trial 3: Are the two charge ions attracted, repelled, or neither?:
Trial 3: Are the two charge ions attracted, repelled, or neither?
8.
Trial 4: Are the two charge ions attracted, repelled, or neither?:
Trial 4: Are the two charge ions attracted, repelled, or neither?
Column B
a.89.876 N
b.79.889 N
c.Attracted
d.44.938 N
e.Neither
f.Repelled
g.269.627 N
h.179.751 N
i.359.502 N
Question 9
How does changing the charge’s value influence the force between the two charges?

As the value of charge 1 __________, the value of the force ___________.

a
increases; increases
b
increases; decreases
c
increases; does not change
d
decreases; does not change

1 answer

To find the numerical values of the electrostatic force between two charges using Coulomb’s Law, we can express it with the formula:

\[ F = k \frac{|q_1 \times q_2|}{r^2} \]

where:

  • \( F \) is the force between the charges,
  • \( k \) is Coulomb's constant (\(8.99 \times 10^9 , \text{N m}^2/\text{C}^2\)),
  • \( q_1 \) and \( q_2 \) are the magnitudes of the charges,
  • \( r \) is the distance between the charges.

For your case, \( q_2 = 8 , \mu C = 8 \times 10^{-6} , C \) and the distance \( r = 0.04 , m \) (4 cm). You would adjust \( q_1 \) for Trials 1-4.

Let's fill in the results based on the provided information, assuming the following values for \( q_1 \) for the trials:

  1. Trial 1: \( q_1 = 10 , \mu C = 10 \times 10^{-6} , C \)
  2. Trial 2: \( q_1 = 5 , \mu C = 5 \times 10^{-6} , C \)
  3. Trial 3: \( q_1 = 1 , \mu C = 1 \times 10^{-6} , C \)
  4. Trial 4: \( q_1 = 20 , \mu C = 20 \times 10^{-6} , C \)

Calculate the forces:

  1. For Trial 1: \[ F_1 = k \frac{|10 \times 10^{-6} \times 8 \times 10^{-6}|}{(0.04)^2} \approx 89.876 , N \]

  2. For Trial 2: \[ F_2 = k \frac{|5 \times 10^{-6} \times 8 \times 10^{-6}|}{(0.04)^2} \approx 44.938 , N \]

  3. For Trial 3: \[ F_3 = k \frac{|1 \times 10^{-6} \times 8 \times 10^{-6}|}{(0.04)^2} \approx 8.9876 , N \]

  4. For Trial 4: \[ F_4 = k \frac{|20 \times 10^{-6} \times 8 \times 10^{-6}|}{(0.04)^2} \approx 179.751 , N \]

Responses:

| Trial | Force Calculation | Force | Attraction/Repulsion | |-------|------------------|----------|----------------------| | 1 | \( F \approx 89.876 , N \) | 89.876 N | Repelled | | 2 | \( F \approx 44.938 , N \) | 44.938 N | Repelled | | 3 | \( F \approx 8.9876 , N \) | 8.9876 N | Repelled | | 4 | \( F \approx 179.751 , N \) | 179.751 N | Repelled |

For charges of the same sign:

  • All trials will result in repulsion.

Thus, the answers filled in would be:

Column A

  1. Trial 1: Force = 89.876 N
  2. Trial 2: Force = 44.938 N
  3. Trial 3: Force = 8.9876 N
  4. Trial 4: Force = 179.751 N
  5. Trial 1: Are the two charge ions attracted, repelled, or neither?: Repelled
  6. Trial 2: Are the two charge ions attracted, repelled, or neither?: Repelled
  7. Trial 3: Are the two charge ions attracted, repelled, or neither?: Repelled
  8. Trial 4: Are the two charge ions attracted, repelled, or neither?: Repelled

Column B

  • a. 89.876 N
  • d. 44.938 N
  • i. 8.9876 N
  • h. 179.751 N
  • f. Repelled (for all trials)

Question 9 As the value of charge 1 increases, the value of the force increases. So the correct answer is: a. increases; increases.

Similar Questions
  1. Question 10Coulomb's Law PhET Simulation: Investigation of How Magnitude (size) of Charge Affects Electrostatic Force Part 2 For
    1. answers icon 1 answer
  2. Question 10Coulomb's Law PhET Simulation: Investigation of How Magnitude (size) of Charge Affects Electrostatic Force Part 2 For
    1. answers icon 1 answer
  3. Question 10Coulomb's Law PhET Simulation: Investigation of How Magnitude (size) of Charge Affects Electrostatic Force Part 2 For
    1. answers icon 1 answer
  4. Question 8Coulomb's Law PhET Simulation: Investigation of How Magnitude (size) of Charge Affects Electrostatic Force Part 1 For
    1. answers icon 1 answer
more similar questions