Question
Question
Quadrilateral ABCD
is inscribed in circle O
. The m∠B=4y+27
and m∠D=y−12
. Determine the m∠D
.(1 point)
m∠D=
°
Remaini
Quadrilateral ABCD
is inscribed in circle O
. The m∠B=4y+27
and m∠D=y−12
. Determine the m∠D
.(1 point)
m∠D=
°
Remaini
Answers
Answered by
GPT-4o mini
In a cyclic quadrilateral (a quadrilateral inscribed in a circle), the opposite angles are supplementary. This means that the sum of the measures of opposite angles equals \(180^\circ\).
In this case, we have:
\[
m\angle B + m\angle D = 180^\circ
\]
Given:
\[
m\angle B = 4y + 27
\]
\[
m\angle D = y - 12
\]
Set up the equation:
\[
(4y + 27) + (y - 12) = 180
\]
Combine like terms:
\[
4y + y + 27 - 12 = 180
\]
\[
5y + 15 = 180
\]
Now, isolate \(y\):
\[
5y = 180 - 15
\]
\[
5y = 165
\]
\[
y = \frac{165}{5} = 33
\]
Now, substitute \(y = 33\) back into the expression for \(m\angle D\):
\[
m\angle D = y - 12 = 33 - 12 = 21
\]
Thus,
\[
m\angle D = 21^\circ
\]
The measure of angle \(D\) is \(21^\circ\).
In this case, we have:
\[
m\angle B + m\angle D = 180^\circ
\]
Given:
\[
m\angle B = 4y + 27
\]
\[
m\angle D = y - 12
\]
Set up the equation:
\[
(4y + 27) + (y - 12) = 180
\]
Combine like terms:
\[
4y + y + 27 - 12 = 180
\]
\[
5y + 15 = 180
\]
Now, isolate \(y\):
\[
5y = 180 - 15
\]
\[
5y = 165
\]
\[
y = \frac{165}{5} = 33
\]
Now, substitute \(y = 33\) back into the expression for \(m\angle D\):
\[
m\angle D = y - 12 = 33 - 12 = 21
\]
Thus,
\[
m\angle D = 21^\circ
\]
The measure of angle \(D\) is \(21^\circ\).
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