From the way you have stated the problem,
012 = 0 + 1 + 2 = 3 = 120 = 102 etc.
Does that change your mind?
a three digit number is chosen at random. what is the probability that the sum of the digits is less than 6?
i got 3.78% but im not sure if that is correct. I assumed that there were three possible outcomes because 012 would just be considered 12
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