△BCE∼△JKL

. If m∠B=89°
, m∠C=13°
, and m∠E=78°
what is m∠J
?(1 point)
m∠J=

1 answer

Since triangles \(\triangle BCE\) and \(\triangle JKL\) are similar, their corresponding angles are equal.

In triangle \(\triangle BCE\), the angles are given as:

  • \(m∠B = 89°\)
  • \(m∠C = 13°\)
  • \(m∠E = 78°\)

To find \(m∠J\) in triangle \(\triangle JKL\), we can look for the corresponding angle to \(m∠B\).

Since the angles in a triangle must sum up to \(180°\):

\[ m∠B + m∠C + m∠E = 89° + 13° + 78° = 180° \]

From the similarity of the triangles, we conclude:

\[ m∠J = m∠B = 89° \]

Thus,

\[ m∠J = 89° \]

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