Asked by ANGELICA

inverse of y=-√(9-x^2 )
Answered by Henry
Y = -sqrt(9-X^2).
X = -sqrt(9-Y^2)
Square both sides:
X^2 = 1(9 - Y^2)
X^2 = 9 - Y^2
Y^2 = 9 - X^2
Y = sqrt (9 - X^2)