Asked by Slim Shady
Solve for D
d-2/d-3 = 1/-m
d-2/d-3 = 1/-m
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To solve for \( d \) in the equation
\[
\frac{d-2}{d-3} = \frac{1}{-m},
\]
we'll first eliminate the fractions by cross-multiplying:
\[
(d - 2)(-m) = (d - 3)(1).
\]
Expanding both sides gives:
\[
-m(d - 2) = d - 3.
\]
Distributing on the left side:
\[
-md + 2m = d - 3.
\]
Next, we can rearrange the terms to isolate \( d \). First, add \( md \) to both sides and add 3 to both sides:
\[
2m + 3 = d + md.
\]
Factoring out \( d \) on the right side:
\[
2m + 3 = d(1 + m).
\]
Now, we can solve for \( d \) by dividing both sides by \( 1 + m \):
\[
d = \frac{2m + 3}{1 + m}.
\]
Thus, the solution for \( d \) is:
\[
\boxed{\frac{2m + 3}{1 + m}}.
\]
\[
\frac{d-2}{d-3} = \frac{1}{-m},
\]
we'll first eliminate the fractions by cross-multiplying:
\[
(d - 2)(-m) = (d - 3)(1).
\]
Expanding both sides gives:
\[
-m(d - 2) = d - 3.
\]
Distributing on the left side:
\[
-md + 2m = d - 3.
\]
Next, we can rearrange the terms to isolate \( d \). First, add \( md \) to both sides and add 3 to both sides:
\[
2m + 3 = d + md.
\]
Factoring out \( d \) on the right side:
\[
2m + 3 = d(1 + m).
\]
Now, we can solve for \( d \) by dividing both sides by \( 1 + m \):
\[
d = \frac{2m + 3}{1 + m}.
\]
Thus, the solution for \( d \) is:
\[
\boxed{\frac{2m + 3}{1 + m}}.
\]
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