Based on the behaviors described, the correct choice is:
\( f(x) = 3^x \)
Here's the reasoning:
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No Maximum Value: The function must grow indefinitely, meaning as \( x \) increases, \( f(x) \) keeps increasing without reaching a maximum.
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Always Increasing: The function must be strictly increasing, which means that as you increase \( x \), \( f(x) \) also increases.
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Not Negative: The function values must always be zero or positive.
Now, let's analyze the options:
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\( f(x) = \log x \): This function is not defined for \( x \leq 0 \) and increases, but it has no maximum value. However, it does not meet the "not negative" criterion as it is negative for \( 0 < x < 1 \).
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\( f(x) = 3^x \): This function is always positive, always increasing, and has no maximum value. As \( x \) increases, \( f(x) \) increases exponentially.
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\( f(x) = x \): This function is indeed always increasing and has no maximum value. However, it meets the "not negative" criterion, but it is strictly increasing and unbounded, which could also be a candidate.
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\( f(x) = x^2 \): This function has a minimum value at \( x = 0 \) and isn’t strictly increasing for all \( x \) (it decreases for \( x < 0 \)).
Based on the overall behaviors described, both \( f(x) = 3^x \) and \( f(x) = x \) can be legitimate answers. However, since \( 3^x \) is a clearer example of a function that grows without bound (exponentially), it is the best fit for the description given.
Thus, the best option is \( f(x) = 3^x \).