To find a point on the line described by the equation \( y = -\frac{1}{2}x + 8 \), we can substitute a specific value for \( x \) and calculate the corresponding \( y \) value.
Let's compute the point when \( x = 0 \):
\[ y = -\frac{1}{2}(0) + 8 = 8 \]
This gives us the point \( (0, 8) \).
Now let's try another value for \( x \), say \( x = 2 \):
\[ y = -\frac{1}{2}(2) + 8 = -1 + 8 = 7 \]
This gives us the point \( (2, 7) \).
You can use these points, \( (0, 8) \) and \( (2, 7) \), both of which lie on the line described by the equation.
Thus, both points \( (0, 8) \) and \( (2, 7) \) are valid points on the line.