Question

Two workers are pushing on the same large crate. One worker pushes east with a force of 875 N, while the other worker pushes north with a force of 960 N. Friction between the crate and the floor is directed west with a force of 80 N and south with a force of 105 N. Assuming drag due to air resistance is negligible, what are the total north-south net forces and the total east-west net forces acting on the crate, causing it to accelerate across the floor?(1 point)
Responses

855 N to the south and 759 N to the west
855 N to the south and 759 N to the west

795 N to the north and 855 N to the east
795 N to the north and 855 N to the east

855 N to the north and 795 N to the east
855 N to the north and 795 N to the east

795 N to the south and 855 N to the west

Answer 1

To find the total net forces acting on the crate, we break down the forces into their north-south and east-west components.

**North-South Forces:**
- North push: 960 N (from the worker)
- South force (friction): 105 N

Net North-South Force = North push - South friction
Net North-South Force = 960 N - 105 N = 855 N to the north

**East-West Forces:**
- East push: 875 N (from the worker)
- West force (friction): 80 N

Net East-West Force = East push - West friction
Net East-West Force = 875 N - 80 N = 795 N to the east

Thus, the total net forces are:
- 855 N to the north (not to the south)
- 795 N to the east

However, there seems to be a discrepancy in the provided options matching the calculations. Here are the summarized results again:

- Total North-South net force: **855 N to the north**
- Total East-West net force: **795 N to the east**

Based on your options, none match exactly as per our calculations. Please verify the choices again.