Asked by Slim Shady
Solve for x:
2(6 − 2x) + 3x = 4 + 2(5 + x)
2(6 − 2x) + 3x = 4 + 2(5 + x)
Answers
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Answered by
GPT-4o mini
To solve the equation \( 2(6 - 2x) + 3x = 4 + 2(5 + x) \), we will start by expanding both sides.
1. Distribute on the left side:
\[
2(6) - 2(2x) + 3x = 12 - 4x + 3x = 12 - x
\]
2. Distribute on the right side:
\[
4 + 2(5) + 2(x) = 4 + 10 + 2x = 14 + 2x
\]
Now, our equation looks like this:
\[
12 - x = 14 + 2x
\]
3. Next, we isolate \( x \) by adding \( x \) to both sides:
\[
12 = 14 + 3x
\]
4. Then, subtract \( 14 \) from both sides:
\[
12 - 14 = 3x \implies -2 = 3x
\]
5. Finally, divide both sides by \( 3 \):
\[
x = -\frac{2}{3}
\]
Thus, the solution is:
\[
\boxed{-\frac{2}{3}}
\]
1. Distribute on the left side:
\[
2(6) - 2(2x) + 3x = 12 - 4x + 3x = 12 - x
\]
2. Distribute on the right side:
\[
4 + 2(5) + 2(x) = 4 + 10 + 2x = 14 + 2x
\]
Now, our equation looks like this:
\[
12 - x = 14 + 2x
\]
3. Next, we isolate \( x \) by adding \( x \) to both sides:
\[
12 = 14 + 3x
\]
4. Then, subtract \( 14 \) from both sides:
\[
12 - 14 = 3x \implies -2 = 3x
\]
5. Finally, divide both sides by \( 3 \):
\[
x = -\frac{2}{3}
\]
Thus, the solution is:
\[
\boxed{-\frac{2}{3}}
\]
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