Question

Allison has a bag that contains pineapple chews, lemon chews, and lime chews. She performs an experiment. Allison randomly removes a chew from the bag, records the result, and returns the chew to the bag. Allison performs the experiment 36 times. The results are shown below:
A pineapple chew was selected 5 times.
A lemon chew was selected 25 times.
A lime chew was selected 6 times.

Based on these results, express the probability that the next chew Allison removes from the bag will be lemon or lime as a percent to the nearest whole number.

Answer 1

To find the probability that the next chew Allison removes from the bag will be either a lemon or a lime chew, we first need to determine the total number of selections and how many of those resulted in a lemon or lime chew.

From the results provided:
- Pineapple chews selected: 5 times
- Lemon chews selected: 25 times
- Lime chews selected: 6 times

The total number of selections is:

\[
5 + 25 + 6 = 36
\]

Now, we need to find the total number of times a lemon or lime chew was selected:

\[
\text{Lemon chews} + \text{Lime chews} = 25 + 6 = 31
\]

Next, we can calculate the probability of selecting either a lemon or a lime chew by using the formula for probability:

\[
P(\text{Lemon or Lime}) = \frac{\text{Number of Lemon or Lime chews}}{\text{Total number of chews selected}} = \frac{31}{36}
\]

Now, to express this probability as a percentage, we first convert the fraction to a decimal:

\[
\frac{31}{36} \approx 0.8611
\]

Then, we multiply by 100 to find the percentage:

\[
0.8611 \times 100 \approx 86.11
\]

Rounding this to the nearest whole number gives us:

\[
\approx 86\%
\]

Thus, the probability that the next chew Allison removes from the bag will be either a lemon or a lime is **86%**.