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A line segment has endpoints (0, 5) and (6, 5). After the line segment is reflected across the x-axis, how long will it be?(1 p...Asked by woosan♥
A line segment has endpoints (0, 5)
and (6, 5)
. After the line segment is reflected across the x
-axis, how long will it be?(1 point)
Responses
6 units
6 units
11 units
11 units
1 unit
1 unit
5 units
and (6, 5)
. After the line segment is reflected across the x
-axis, how long will it be?(1 point)
Responses
6 units
6 units
11 units
11 units
1 unit
1 unit
5 units
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the length of the line segment after it is reflected across the x-axis, we first need to determine the coordinates of the endpoints after the reflection.
The original endpoints are (0, 5) and (6, 5). When reflected across the x-axis, the y-coordinates of the points change sign. Therefore, the new endpoints after reflection will be:
1. (0, 5) becomes (0, -5)
2. (6, 5) becomes (6, -5)
Now, we can calculate the length of the line segment between these new endpoints (0, -5) and (6, -5). The length of a line segment can be calculated using the distance formula:
\[
\text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
Substituting in the coordinates of the new endpoints:
- \(x_1 = 0\), \(y_1 = -5\)
- \(x_2 = 6\), \(y_2 = -5\)
The distance calculation becomes:
\[
\text{Distance} = \sqrt{(6 - 0)^2 + (-5 - (-5))^2}
\]
\[
= \sqrt{(6)^2 + (0)^2}
\]
\[
= \sqrt{36 + 0}
\]
\[
= \sqrt{36}
\]
\[
= 6
\]
Thus, the length of the line segment after it is reflected across the x-axis will be **6 units**.
The original endpoints are (0, 5) and (6, 5). When reflected across the x-axis, the y-coordinates of the points change sign. Therefore, the new endpoints after reflection will be:
1. (0, 5) becomes (0, -5)
2. (6, 5) becomes (6, -5)
Now, we can calculate the length of the line segment between these new endpoints (0, -5) and (6, -5). The length of a line segment can be calculated using the distance formula:
\[
\text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
Substituting in the coordinates of the new endpoints:
- \(x_1 = 0\), \(y_1 = -5\)
- \(x_2 = 6\), \(y_2 = -5\)
The distance calculation becomes:
\[
\text{Distance} = \sqrt{(6 - 0)^2 + (-5 - (-5))^2}
\]
\[
= \sqrt{(6)^2 + (0)^2}
\]
\[
= \sqrt{36 + 0}
\]
\[
= \sqrt{36}
\]
\[
= 6
\]
Thus, the length of the line segment after it is reflected across the x-axis will be **6 units**.
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