To solve for the vertical intercept \( b \) in the equation \( y = mx + b \), we need to find the slope \( m \) and then use one of the points given.
From the points provided, we have:
- Point 1: \( (2, 40) \)
- Point 2: \( (4, 60) \)
First, let's calculate the slope \( m \) using the formula:
\[ m = \frac{y_2 - y_1}{x_2 - x_1} \]
Using the points \( (2, 40) \) and \( (4, 60) \):
\[ m = \frac{60 - 40}{4 - 2} = \frac{20}{2} = 10 \]
Now we have the slope \( m = 10 \).
Next, we can use one of the points to solve for \( b \). Let's use the point \( (2, 40) \):
\[ y = mx + b \] \[ 40 = 10(2) + b \] \[ 40 = 20 + b \] \[ b = 40 - 20 \] \[ b = 20 \]
So the value of \( b \), the vertical intercept, is \( 20 \).