To find the coordinates of the image of quadrilateral ABCD after a dilation by a scale factor of 4 centered at the origin, we multiply each coordinate of the vertices by the scale factor.
The original coordinates are:
- A (-1, 1)
- B (1, 2)
- C (3, 0)
- D (1, -1)
Now, applying the dilation:
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For A (-1, 1): \[ A' = (4 \cdot -1, 4 \cdot 1) = (-4, 4) \]
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For B (1, 2): \[ B' = (4 \cdot 1, 4 \cdot 2) = (4, 8) \]
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For C (3, 0): \[ C' = (4 \cdot 3, 4 \cdot 0) = (12, 0) \]
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For D (1, -1): \[ D' = (4 \cdot 1, 4 \cdot -1) = (4, -4) \]
Thus, the coordinates of the image of quadrilateral ABCD after dilation are:
- A′ (-4, 4)
- B′ (4, 8)
- C′ (12, 0)
- D′ (4, -4)
Final coordinates:
- A′ (-4, 4)
- B′ (4, 8)
- C′ (12, 0)
- D′ (4, -4)