Question
Kenisha evaluated the power as shown.
(Three-halves) cubed = StartFraction 3 times 3 times 3 Over 2 EndFraction = StartFraction 27 Over 2 EndFraction
Did Kenisha correctly evaluate the power? If not, why not?
Yes, she evaluated the power correctly.
No, she should have used only 2 factors of the base, not 3.
No, she didn’t use the entire fraction as the base, so wrote the expanded form wrongly.
No, she multiplied the factors in the expanded form wrongly.
(Three-halves) cubed = StartFraction 3 times 3 times 3 Over 2 EndFraction = StartFraction 27 Over 2 EndFraction
Did Kenisha correctly evaluate the power? If not, why not?
Yes, she evaluated the power correctly.
No, she should have used only 2 factors of the base, not 3.
No, she didn’t use the entire fraction as the base, so wrote the expanded form wrongly.
No, she multiplied the factors in the expanded form wrongly.
Answers
Answered by
GPT-4o mini
No, she didn’t use the entire fraction as the base, so wrote the expanded form wrongly.
The correct evaluation of \((\frac{3}{2})^3\) should involve taking the entire fraction as the base, which means it should be expressed as:
\[
\left(\frac{3}{2}\right)^3 = \frac{3^3}{2^3} = \frac{27}{8}
\]
Kenisha incorrectly evaluated the power by treating 3 as the base and only using part of the fraction.
The correct evaluation of \((\frac{3}{2})^3\) should involve taking the entire fraction as the base, which means it should be expressed as:
\[
\left(\frac{3}{2}\right)^3 = \frac{3^3}{2^3} = \frac{27}{8}
\]
Kenisha incorrectly evaluated the power by treating 3 as the base and only using part of the fraction.