To solve for the number of wolves in Year 1, Year 2, and Year 3, we start with the equations given:
- Year 1: \( z \)
- Year 2: \( 7 + z \)
- Year 3: \( 3z - 3 \)
According to the problem, the number of wolves in Year 2 is equal to the number of wolves in Year 3:
\[ 7 + z = 3z - 3 \]
Now, we can solve for \( z \):
- Rearranging gives: \[ 7 + z + 3 = 3z \] \[ 10 = 3z - z \] \[ 10 = 2z \]
- Dividing both sides by 2: \[ z = 5 \]
Now we can find the number of wolves each year:
- Year 1: \( z = 5 \)
- Year 2: \( 7 + z = 7 + 5 = 12 \)
- Year 3: \( 3z - 3 = 3(5) - 3 = 15 - 3 = 12 \)
Both Year 2 and Year 3 have 12 wolves, confirming our calculations.
Next, we need to write an expression for Year 4 of the study, given as \( (x + a)(x - b) \), where \( a \) and \( b \) are whole numbers greater than 1 and less than 10. Let's choose:
- \( a = 3 \)
- \( b = 2 \)
Thus, the expression for Year 4 would be:
\[ (x + 3)(x - 2) \]
Now, we will multiply the two terms:
\[ (x + 3)(x - 2) = x^2 - 2x + 3x - 6 = x^2 + x - 6 \]
Therefore, the expression Jin uses to describe the number of wolves in Year 4 of the study is:
\[ x^2 + x - 6 \]