A seesaw spinner designed for children aged 6–8 years old has 4 seats. The total weight limit for 4 riders is 170 pounds. Four children want to use the seesaw spinner. Three of the four children already weigh a total of 120 pounds. At most, how heavy can the fourth child weigh for the total weight to be within the limit? Write the missing operation and symbol so the inequality will represent the maximum weight of the fourth player. You will find the option to add inequality symbols in the Comparison (<)

Question

keyboard.(1 point)
w

120
170

Answer 1

To find the maximum weight of the fourth child, we start by letting \( w \) represent the weight of the fourth child. We know the total weight limit for the four children is 170 pounds and the combined weight of the first three children is 120 pounds.

We can express this as an inequality:

\[ 120 + w \leq 170 \]

This inequality shows that the total weight (120 pounds from the three children plus the weight of the fourth child) must be less than or equal to 170 pounds.

To isolate \( w \), we can rewrite the inequality:

\[ w \leq 170 - 120 \]

Therefore, the operation and symbol that complete the inequality are:

w ≤ 170 - 120.

So, the final inequality representing the maximum weight of the fourth child is:

\[ w \leq 50 \]

In summary, the fourth child can weigh at most 50 pounds for the total weight to be within the limit.