Asked by joyce
-6q^2 -40q - 50 how do you solve this i am factoring and having problems
Answers
Answered by
Kate
Use the quadratic formula
(40 +/- sqrt((-40)^2 - 4(-6)(-50) ))/(2(-6))
what ever that comes out to be
(40 +/- sqrt((-40)^2 - 4(-6)(-50) ))/(2(-6))
what ever that comes out to be
Answered by
Henry
-6q^2 - 40q -50.
Factor using the AC method:
-2(3q^2 + 20q + 25)
A*C = 3*25 = 75 = 5*15.
Replace 20q with 5q + 15q:
-2(3q^2 +5q+15q + 25).
Group the 4 terms in pairs that can
be factored:
-2(3q^2+15q + 5q+25).
Factor the 2 pairs:
-2(3q(q+5) + 5(q+5).
Factor out q+5:
-2((q + 5) (3q + 5)).
Factor using the AC method:
-2(3q^2 + 20q + 25)
A*C = 3*25 = 75 = 5*15.
Replace 20q with 5q + 15q:
-2(3q^2 +5q+15q + 25).
Group the 4 terms in pairs that can
be factored:
-2(3q^2+15q + 5q+25).
Factor the 2 pairs:
-2(3q(q+5) + 5(q+5).
Factor out q+5:
-2((q + 5) (3q + 5)).
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