Question

The equation of a line in point-slope form is y−2=−5(x+3) . Write this equation in slope intercept form y=mx+b . (1 point) Responses y=5x−13 y is equal to 5 x minus 13 y=−5x−13 y is equal to negative 5 x minus 13 y=−5x+5 y is equal to negative 5 x plus 5 y=−5x+13

Answer 1

To convert the equation from point-slope form (\(y - 2 = -5(x + 3)\)) to slope-intercept form (\(y = mx + b\)), follow these steps:

1. Start with the given equation:
\[
y - 2 = -5(x + 3)
\]

2. Distribute \(-5\) on the right side:
\[
y - 2 = -5x - 15
\]

3. Add \(2\) to both sides to isolate \(y\):
\[
y = -5x - 15 + 2
\]
\[
y = -5x - 13
\]

Now, the equation in slope-intercept form is:
\[
y = -5x - 13
\]

The correct response is:
**y = -5x - 13**.