Asked by Deja
How many liters of 20% alcohol solution should Maria mix with 50 liters of a 60% alcohol solution to obtain a 30% solution?
Answers
Answered by
bobpursley
ok, in the 50 liters, you get 30 liters of alcohol content. In the final mixture, you want 30 percent, so
.30(V+50)=30+.2V
check that. solve for V, the volume of 20percent.
.30(V+50)=30+.2V
check that. solve for V, the volume of 20percent.
Answered by
Deja
Perfect thx!!
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