p-(4,6)

Translate figure PQRS 6 units down and 2 units to the right. What are the coordinates of P′ ? (1 point) Responses (10, 4) left parenthesis 10 comma 4 right parenthesis (2, 0) left parenthesis 2 comma 0 right parenthesis (2, 12) left parenthesis 2 comma 12 right parenthesis (6, 0)

1 answer

To translate the point P, which is at coordinates \( (4, 6) \), 6 units down and 2 units to the right, we can follow these steps:

  1. Move 6 units down: This means we subtract 6 from the y-coordinate.

    • New y-coordinate: \( 6 - 6 = 0 \)
  2. Move 2 units to the right: This means we add 2 to the x-coordinate.

    • New x-coordinate: \( 4 + 2 = 6 \)

So, the new coordinates of \( P' \) after the translation will be \( (6, 0) \).

Therefore, the correct answer is \( (6, 0) \).