Question

The equation of a line in point-slope form is y−2=−5(x+3)
.

Write this equation in slope intercept form y=mx+b
.

(1 point)
Responses

y=−5x−13
y is equal to negative 5 x minus 13

y=−5x+13
y is equal to negative 5 x plus 13

y=5x−13
y is equal to 5 x minus 13

y=−5x+5

Answer 1

To convert the equation from point-slope form to slope-intercept form, we start with the given point-slope equation:

\[
y - 2 = -5(x + 3)
\]

First, we will distribute \(-5\) on the right side:

\[
y - 2 = -5x - 15
\]

Next, we will add \(2\) to both sides to solve for \(y\):

\[
y = -5x - 15 + 2
\]

This simplifies to:

\[
y = -5x - 13
\]

So, the equation in slope-intercept form is:

\[
y = -5x - 13
\]

Therefore, the correct response is:

**y = −5x − 13**