Question

The equation of a line in point-slope form is y−2=−5(x+3)
.

Write this equation in slope intercept form y=mx+b
.

(1 point)
Responses

y=−5x+5

y=−5x+13

y=5x−13

y=−5x−13

Answer 1

To convert the equation from point-slope form \( y - 2 = -5(x + 3) \) to slope-intercept form \( y = mx + b \), follow these steps:

1. Distribute \(-5\) on the right side:
\[
y - 2 = -5x - 15
\]

2. Add \(2\) to both sides to isolate \(y\):
\[
y = -5x - 15 + 2
\]
\[
y = -5x - 13
\]

So, the slope-intercept form of the equation is:
\[
y = -5x - 13
\]

The correct response is:
**y = -5x - 13**.