Use the table of the masses of several objects to answer the question. Object Mass (grams) paper clip 1.0

penny 2.5
book 860
cereal box 500
small pot 1,200

Between which two objects is gravitational attraction the greatest if placed 1 meter apart? (1 point)

between the book and the cereal box

between the book and the cereal box

between the penny and the small pot

between the penny and the small pot

between the small pot and the book

between the small pot and the book

between the paper clip and the penny

1 answer

The gravitational attraction between two objects can be calculated using Newton's law of universal gravitation, which states that the gravitational force \( F \) between two masses \( m_1 \) and \( m_2 \) separated by a distance \( r \) is given by:

\[ F = G \frac{m_1 m_2}{r^2} \]

Where \( G \) is the gravitational constant. Given that the distance \( r \) is the same (1 meter) for all pairs, the gravitational attraction will depend solely on the product of their masses.

Let's evaluate the different pairs of objects using their masses:

  1. Between the book (860 g) and the cereal box (500 g): \[ F_1 = 860 \times 500 = 430,000 \]

  2. Between the penny (2.5 g) and the small pot (1,200 g): \[ F_2 = 2.5 \times 1,200 = 3,000 \]

  3. Between the small pot (1,200 g) and the book (860 g): \[ F_3 = 1,200 \times 860 = 1,032,000 \]

  4. Between the paper clip (1.0 g) and the penny (2.5 g): \[ F_4 = 1.0 \times 2.5 = 2.5 \]

Now, comparing the results:

  • \( F_1 = 430,000 \)
  • \( F_2 = 3,000 \)
  • \( F_3 = 1,032,000 \)
  • \( F_4 = 2.5 \)

The greatest gravitational attraction is between the small pot and the book, with a gravitational force of 1,032,000. So the answer is between the small pot and the book.