The energy of a wave is proportional to the square of its amplitude. If we denote the amplitude of wave X as \( A_X = 2 \) meters and the amplitude of wave Y as \( A_Y = 6 \) meters, we can calculate the energy of each wave as follows:
- Energy of wave X: \( E_X \propto A_X^2 = 2^2 = 4 \)
- Energy of wave Y: \( E_Y \propto A_Y^2 = 6^2 = 36 \)
To compare the energies, we can form the ratio of the energy of wave Y to the energy of wave X:
\[ \frac{E_Y}{E_X} = \frac{36}{4} = 9 \]
This means that the energy of wave Y is 9 times greater than the energy of wave X.
Thus, the correct answer is:
B. It is nine times as great.