In the picture above, if the cue stick strikes the 0.22-kg cue ball with a force of 1.8 N, what will be the acceleration of the cue ball?

A.
8.4 m/s2
B.
0.4 m/s2
C.
0.46 m/s2
D.
8.2 m/s2

1 answer

To find the acceleration of the cue ball, we can use Newton's second law of motion, which states:

\[ F = m \cdot a \]

Where:

  • \( F \) is the force applied (in Newtons),
  • \( m \) is the mass (in kg), and
  • \( a \) is the acceleration (in m/s²).

Rearranging the formula to solve for acceleration, we get:

\[ a = \frac{F}{m} \]

Given:

  • \( F = 1.8 , \text{N} \)
  • \( m = 0.22 , \text{kg} \)

Now substituting the values into the equation:

\[ a = \frac{1.8 , \text{N}}{0.22 , \text{kg}} \]

Calculating:

\[ a \approx 8.18 , \text{m/s}² \]

Rounding this to two decimal places gives:

\[ a \approx 8.2 , \text{m/s}² \]

Thus, the answer is:

D. 8.2 m/s²