Question
Force Acting on Cart Cart Acceleration
(N) (m/s^2)
1 0.2
2 0.4
5 1.0
6 1.2
? 2.6
Scroll down to ensure you answer BOTH questions on this page.
Some students measure the acceleration of a wheeled cart being acted on by varying forces. The students record their data in the table shown below.
According to the data table, how much force is acting on the cart when the students measure an acceleration of 2.6 m/s²? (*Hint: the cart is the same cart for each trial).
HINT: Refer to your STAAR Reference Sheet.
(1 point)
Enter a whole number only. No decimal, space, or symbols/letters.
N
(N) (m/s^2)
1 0.2
2 0.4
5 1.0
6 1.2
? 2.6
Scroll down to ensure you answer BOTH questions on this page.
Some students measure the acceleration of a wheeled cart being acted on by varying forces. The students record their data in the table shown below.
According to the data table, how much force is acting on the cart when the students measure an acceleration of 2.6 m/s²? (*Hint: the cart is the same cart for each trial).
HINT: Refer to your STAAR Reference Sheet.
(1 point)
Enter a whole number only. No decimal, space, or symbols/letters.
N
Answers
GPT-4o mini
To determine the force acting on the cart when the acceleration is 2.6 m/s², we can use the relationship between force, mass, and acceleration given by Newton's second law of motion:
\[ F = m \cdot a \]
From the data provided, we can first find the mass (m) of the cart using the known forces and accelerations. We can do this using one of the pairs in the table.
Let's use the pair (1 N, 0.2 m/s²):
1. Calculate the mass (m):
\[ m = \frac{F}{a} = \frac{1 \, \text{N}}{0.2 \, \text{m/s}^2} = 5 \, \text{kg} \]
Now that we know the mass of the cart is 5 kg, we can calculate the force for an acceleration of 2.6 m/s².
2. Use the mass to find the required force:
\[ F = m \cdot a = 5 \, \text{kg} \cdot 2.6 \, \text{m/s}^2 = 13 \, \text{N} \]
Thus, the force acting on the cart when the acceleration is 2.6 m/s² is:
**13**
\[ F = m \cdot a \]
From the data provided, we can first find the mass (m) of the cart using the known forces and accelerations. We can do this using one of the pairs in the table.
Let's use the pair (1 N, 0.2 m/s²):
1. Calculate the mass (m):
\[ m = \frac{F}{a} = \frac{1 \, \text{N}}{0.2 \, \text{m/s}^2} = 5 \, \text{kg} \]
Now that we know the mass of the cart is 5 kg, we can calculate the force for an acceleration of 2.6 m/s².
2. Use the mass to find the required force:
\[ F = m \cdot a = 5 \, \text{kg} \cdot 2.6 \, \text{m/s}^2 = 13 \, \text{N} \]
Thus, the force acting on the cart when the acceleration is 2.6 m/s² is:
**13**