Question
Question
The use of electricity in the US in 1902 was 6.03 x 10^9 kilowatt-hours.
The use of electricity in the US in 1950 was 4.3 x 10^11 kilowatt-hours.
What was the total kilowatt-hours of electricity used during these two years?
(1 point)
Responses
(6.03×109)×(4.3×1011)=25.929×1020=2.6×1019
open paren 6 point 0 3 times 10 to the 9th power close paren times open paren 4 point 3 times 10 to the 11th power close paren is equal to 25 point 9 2 9 times 10 to the 20th power is equal to 2 point 6 times 10 to the 19th power
(6.03×109)+(4.3×1011)=10.33×1020=1.033×1019
open paren 6 point 0 3 times 10 to the 9th power close paren plus open paren 4 point 3 times 10 to the 11th power close paren is equal to 10 point 3 3 times 10 to the 20th power is equal to 1 point 0 3 3 times 10 to the 19th power
(6.03×109)×(4.3×1011)=25.929×102=2.6×101
open paren 6 point 0 3 times 10 to the 9th power close paren times open paren 4 point 3 times 10 to the 11th power close paren is equal to 25 point 9 2 9 times 10 squared is equal to 2 point 6 times 10 to the 1th power
(6.03×109)+(4.3×1011)=0.063×1011+(4.3×1011)=4.3603×1011
open paren 6 point 0 3 times 10 to the 9th power close paren plus open paren 4 point 3 times 10 to the 11th power close paren is equal to 0 point 0 6 3 times 10 to the 11th power plus open paren 4 point 3 times 10 to the 11th power close paren is equal to 4 point 3 6 0 3 times 10 to the 11th power
The use of electricity in the US in 1902 was 6.03 x 10^9 kilowatt-hours.
The use of electricity in the US in 1950 was 4.3 x 10^11 kilowatt-hours.
What was the total kilowatt-hours of electricity used during these two years?
(1 point)
Responses
(6.03×109)×(4.3×1011)=25.929×1020=2.6×1019
open paren 6 point 0 3 times 10 to the 9th power close paren times open paren 4 point 3 times 10 to the 11th power close paren is equal to 25 point 9 2 9 times 10 to the 20th power is equal to 2 point 6 times 10 to the 19th power
(6.03×109)+(4.3×1011)=10.33×1020=1.033×1019
open paren 6 point 0 3 times 10 to the 9th power close paren plus open paren 4 point 3 times 10 to the 11th power close paren is equal to 10 point 3 3 times 10 to the 20th power is equal to 1 point 0 3 3 times 10 to the 19th power
(6.03×109)×(4.3×1011)=25.929×102=2.6×101
open paren 6 point 0 3 times 10 to the 9th power close paren times open paren 4 point 3 times 10 to the 11th power close paren is equal to 25 point 9 2 9 times 10 squared is equal to 2 point 6 times 10 to the 1th power
(6.03×109)+(4.3×1011)=0.063×1011+(4.3×1011)=4.3603×1011
open paren 6 point 0 3 times 10 to the 9th power close paren plus open paren 4 point 3 times 10 to the 11th power close paren is equal to 0 point 0 6 3 times 10 to the 11th power plus open paren 4 point 3 times 10 to the 11th power close paren is equal to 4 point 3 6 0 3 times 10 to the 11th power
Answers
GPT-4o mini
To find the total kilowatt-hours of electricity used during the years 1902 and 1950, we need to add the two values together:
1. **Convert both values to a similar exponent**:
- \( 6.03 \times 10^9 \) kilowatt-hours (for 1902)
- \( 4.3 \times 10^{11} \) kilowatt-hours (for 1950)
2. **Rewrite the first number to have the same exponent as the second**:
- Convert \( 6.03 \times 10^9 \) to the same power of 10 as \( 4.3 \times 10^{11} \):
- \( 6.03 \times 10^9 = 0.0603 \times 10^{11} \)
3. **Now add them**:
- Total = \( 0.0603 \times 10^{11} + 4.3 \times 10^{11} \)
- This is \( 4.3603 \times 10^{11} \)
So the answer is:
- **(6.03×10^9) + (4.3×10^{11}) = 4.3603×10^{11}** (the option that matches this calculation is the last one provided in your question).
1. **Convert both values to a similar exponent**:
- \( 6.03 \times 10^9 \) kilowatt-hours (for 1902)
- \( 4.3 \times 10^{11} \) kilowatt-hours (for 1950)
2. **Rewrite the first number to have the same exponent as the second**:
- Convert \( 6.03 \times 10^9 \) to the same power of 10 as \( 4.3 \times 10^{11} \):
- \( 6.03 \times 10^9 = 0.0603 \times 10^{11} \)
3. **Now add them**:
- Total = \( 0.0603 \times 10^{11} + 4.3 \times 10^{11} \)
- This is \( 4.3603 \times 10^{11} \)
So the answer is:
- **(6.03×10^9) + (4.3×10^{11}) = 4.3603×10^{11}** (the option that matches this calculation is the last one provided in your question).