To analyze the function \( y = -2x^2 + 4x + 6 \), let's first find the x-intercepts by setting \( y = 0 \):
\[ 0 = -2x^2 + 4x + 6 \]
We can rearrange the equation:
\[ -2x^2 + 4x + 6 = 0 \]
Divide the entire equation by -2 to simplify:
\[ x^2 - 2x - 3 = 0 \]
Next, we factor the quadratic:
\[ (x - 3)(x + 1) = 0 \]
Setting each factor to zero gives the x-intercepts:
\[ x - 3 = 0 \quad \Rightarrow \quad x = 3 \] \[ x + 1 = 0 \quad \Rightarrow \quad x = -1 \]
Thus, the x-intercepts are \( x = -1 \) and \( x = 3 \).
Question 1: X-intercepts
X-Intercepts:
- Smaller one first: \( -1, 3 \)
Question 2: Interpretation of the X-Intercepts
The x-intercepts represent the points in time (in whatever time unit is chosen) when the rocket has a height of \( y = 0 \), meaning it is at ground level.
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X-Intercept \( x = -1 \): This intercept occurs before the launch at \( x = -1 \). In the context of the rocket launch, this could represent a theoretical scenario or extension of the model where the rocket has not yet been launched (for instance, if time is represented in seconds, this could correlate to a situation that doesn't correspond to a real launch).
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X-Intercept \( x = 3 \): This intercept represents the rocket returning to the ground at \( x = 3 \) seconds after launch. This means the rocket reaches its maximum height and then descends back to ground level approximately 3 seconds after being launched.
Overall, the x-intercepts inform us not only about the specific moments when the rocket is at ground level but also provide insight into the duration of the rocket's flight.