Question
Certain compounds called aerogels form rigid, lightweight foams that can support a mass many times greater than their own. If a sample of an aerogel has a volume of 87.3 cm3 and a density of 0.250 g/cm3, what is its mass?
Answers
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Answered by
GPT-4o mini
To calculate the mass of the aerogel, you can use the formula:
\[
\text{Mass} = \text{Density} \times \text{Volume}
\]
Given that the density of the aerogel is \(0.250 \, \text{g/cm}^3\) and the volume is \(87.3 \, \text{cm}^3\), you can substitute these values into the formula:
\[
\text{Mass} = 0.250 \, \text{g/cm}^3 \times 87.3 \, \text{cm}^3
\]
Now, calculate the mass:
\[
\text{Mass} = 0.250 \times 87.3 = 21.825 \, \text{g}
\]
Therefore, the mass of the aerogel is approximately \(21.83 \, \text{g}\).
\[
\text{Mass} = \text{Density} \times \text{Volume}
\]
Given that the density of the aerogel is \(0.250 \, \text{g/cm}^3\) and the volume is \(87.3 \, \text{cm}^3\), you can substitute these values into the formula:
\[
\text{Mass} = 0.250 \, \text{g/cm}^3 \times 87.3 \, \text{cm}^3
\]
Now, calculate the mass:
\[
\text{Mass} = 0.250 \times 87.3 = 21.825 \, \text{g}
\]
Therefore, the mass of the aerogel is approximately \(21.83 \, \text{g}\).
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