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Two cells are viewed and measured under a microscope. The approximate diameter of each cell is listed. Cell P: 5.0×10^−4 m Cell...Asked by nagumo
Two cells are viewed and measured under a microscope. The approximate diameter of each cell is listed.
Cell P: 5.0×10−4
m
Cell Q: 3.0×10−5
m
What is the difference in the diameters of the two cells?
(1 point)
Responses
0.002 m
0.002 m
0.047 m
0.047 m
0.05 m
0.05 m
0.00047 m
Cell P: 5.0×10−4
m
Cell Q: 3.0×10−5
m
What is the difference in the diameters of the two cells?
(1 point)
Responses
0.002 m
0.002 m
0.047 m
0.047 m
0.05 m
0.05 m
0.00047 m
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the difference in the diameters of the two cells, we subtract the diameter of Cell Q from the diameter of Cell P.
Cell P: \( 5.0 \times 10^{-4} \, \text{m} \)
Cell Q: \( 3.0 \times 10^{-5} \, \text{m} \)
Now we need to perform the subtraction:
1. Convert \( 3.0 \times 10^{-5} \, \text{m} \) to a comparable power of 10:
\( 3.0 \times 10^{-5} \, \text{m} = 0.00003 \, \text{m} \)
2. To make the subtraction easier, we can express both in the same exponent:
\( 5.0 \times 10^{-4} = 0.0005 \, \text{m} \)
Now we can subtract:
\[
0.0005 \, \text{m} - 0.00003 \, \text{m} = 0.00047 \, \text{m}
\]
Thus, the difference in the diameters of the two cells is \( 0.00047 \, \text{m} \).
So, the correct response is:
**0.00047 m**
Cell P: \( 5.0 \times 10^{-4} \, \text{m} \)
Cell Q: \( 3.0 \times 10^{-5} \, \text{m} \)
Now we need to perform the subtraction:
1. Convert \( 3.0 \times 10^{-5} \, \text{m} \) to a comparable power of 10:
\( 3.0 \times 10^{-5} \, \text{m} = 0.00003 \, \text{m} \)
2. To make the subtraction easier, we can express both in the same exponent:
\( 5.0 \times 10^{-4} = 0.0005 \, \text{m} \)
Now we can subtract:
\[
0.0005 \, \text{m} - 0.00003 \, \text{m} = 0.00047 \, \text{m}
\]
Thus, the difference in the diameters of the two cells is \( 0.00047 \, \text{m} \).
So, the correct response is:
**0.00047 m**
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