To solve the equation \( x^2 + 4x - 1 = 2x + 2 \), we can set up two functions based on the left-hand side and the right-hand side of the equation:
- Let \( f(x) = x^2 + 4x - 1 \)
- Let \( g(x) = 2x + 2 \)
To find the solution set, we need to determine the intersection points of \( f(x) \) and \( g(x) \). This involves solving the equation:
\[ f(x) = g(x) \] \[ x^2 + 4x - 1 = 2x + 2 \]
Next, we rearrange the equation by moving all terms to one side:
\[ x^2 + 4x - 1 - 2x - 2 = 0 \] \[ x^2 + 2x - 3 = 0 \]
Now we can factor the quadratic equation:
\[ (x + 3)(x - 1) = 0 \]
Setting each factor equal to zero gives the possible solutions:
- \( x + 3 = 0 \) ⇒ \( x = -3 \)
- \( x - 1 = 0 \) ⇒ \( x = 1 \)
Thus, the solution set of the original equation \( x^2 + 4x - 1 = 2x + 2 \) is:
\[ { -3, 1 } \]
Summary:
- Functions:
- \( f(x) = x^2 + 4x - 1 \)
- \( g(x) = 2x + 2 \)
- Solution set:
- \( { -3, 1 } \)
So the correct response is: \( f(x) = x^2 + 4x - 1 \), \( g(x) = 2x + 2 \), \( { -3, 1 } \).