Let's simplify the expression \((3x−8)+(2x+5)−(4x−8)\) step by step first.
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Distributing the negative sign: \[ (3x - 8) + (2x + 5) - 4x + 8 \]
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Combining like terms:
- Combine \(3x\), \(2x\), and \(-4x\): \[ 3x + 2x - 4x = (3 + 2 - 4)x = 1x = x \]
- Combine the constants \(-8\), \(+5\), and \(+8\): \[ -8 + 5 + 8 = (-8 + 5 + 8) = 5 \]
Putting it all together, we have: \[ x + 5 \]
Now, let's find the expressions equivalent to this simplified form \(x + 5\):
- \(x - 5\) - Not equivalent.
- \(3x + 2x - 4x - 8 + 5 + 8\) - Equivalent since this simplifies to \(x + 5\).
- \(10x - 21\) - Not equivalent.
- \(3x - 8 + 2x + 5 - 4x - 8\) - Equivalent since this simplifies to \(x + 5\).
- \(x + 5\) - Equivalent.
- \(x - 21\) - Not equivalent.
- \(3x - 8 + 2x + 5 - 4x + 8\) - Equivalent since this simplifies to \(x + 5\).
Therefore, the three expressions that are equivalent to \(x + 5\) are:
- \(3x + 2x - 4x - 8 + 5 + 8\)
- \(3x - 8 + 2x + 5 - 4x - 8\)
- \(x + 5\)
So the correct selections are:
- \(3x + 2x - 4x - 8 + 5 + 8\)
- \(3x - 8 + 2x + 5 - 4x - 8\)
- \(x + 5\)