Ask a New Question

Question

how many milligrams of PbI2 can you dissolve in 300 mL of water at 25 degrees celcius
15 years ago

Answers

DrBob222
PbI2 ==> Pb^+ + 2I^-

Ksp = (Pb^+2)(I^-)^2
Set up an ICE chart, substitute into Ksp expression, and solve for PbI2 solubility. Post your work if you get stuck.
15 years ago

Related Questions

What mass of PbI2 can be formed from 75.0 mL of 0.65 M NaI by adding excess Pb(NO3)2? Pb(NO3)2 +... The Ksp of PbI2 is 8.7x10^-9. Find the solubility of lead(II) iodide on mol/L. a. 1.3x10^-3 b. 9... what would happen if PbI2 were to be ingested into your blood stream? A solution of PbI2 has [Pb2+] = 4.5 x 10-5 and [I-] = 6.5 x 10-4. PbI2 has Ksp = 8.7 x 10-9. Write d... 2KI+Pb(NO3)2=2KNO3+PbI2 suppose a solution containing 1.25g of KI is combined with a solution conta... Lead iodide, PbI2, has a Ksp in water of 7.1e-9 M3 at room temperature. Calculate the solubility... What is the solubility of PbI2 in 0.4 M KI given the solubility constant of PbI2 is 7.1 x 10-9 a... The Ksp of PbI2 is 8.73 × 10-9. Find the solubility of PbI2 in M Please guide me , the I C E tabl...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use