Asked by steve
you need to extend a 2.50 inch diameter pipe, but you only have 1.00 inch diameter pipe on hand.you make a fitting to connect these pipes end to end. if the water is flowing at 6.00cm/s in the wide pipe, how fast will it be flowing through the narrow one?
Answers
Answered by
drwls
According to what is called the continuity equation, the product of
(density)(cross sectional area)(velocity)
is a constant in steady-state flow.
For a liquid such as water, you can assume that the density is constant.
Therefore A*V = constant
Since Area is proprtional to diameter ^2,
D^2*V = constant
Now do the numbers.
(density)(cross sectional area)(velocity)
is a constant in steady-state flow.
For a liquid such as water, you can assume that the density is constant.
Therefore A*V = constant
Since Area is proprtional to diameter ^2,
D^2*V = constant
Now do the numbers.
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