Asked by Miguel
The reaction of a metal ion, M^2+, with EDTA is given in the following equation:
M^2+(aq) + Y^4-(aq) <==> MY^2-(aq)
The EDTA was standardized with a 0.04 M Zn^2+ solution. 25.05 mL of EDTA solution was used to titrate the Zn^2+ solution. From this standardization, calculate the concentration of the EDTA solution.
Thanks in advance!
M^2+(aq) + Y^4-(aq) <==> MY^2-(aq)
The EDTA was standardized with a 0.04 M Zn^2+ solution. 25.05 mL of EDTA solution was used to titrate the Zn^2+ solution. From this standardization, calculate the concentration of the EDTA solution.
Thanks in advance!
Answers
Answered by
DrBob222
25.05 mL EDTA x M EDTA = ?mL Zn x 0.04 M Zn.
You didn't post the mL of the Zn solution used. Plug into the equation above and solve for M EDTA.
You didn't post the mL of the Zn solution used. Plug into the equation above and solve for M EDTA.
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