To calculate the change in gallons of water in the pool, you need to use the formula:
\[ \text{Gallons of water in the pool} , (g) = \text{Initial number of gallons of water} + (\text{Change in gallons per hour} \times \text{Time in hours}) \]
Given:
- Initial number of gallons = 250
- Change in gallons per hour = 500
You can rewrite the formula as:
\[ g = 250 + (500 \times t) \]
Where \( t \) represents the time in hours.
Now, let's calculate the gallons of water in the pool for each hour from 0 to 10:
For \( t = 0 \): \[ g = 250 + (500 \times 0) = 250 \]
For \( t = 1 \): \[ g = 250 + (500 \times 1) = 250 + 500 = 750 \]
For \( t = 2 \): \[ g = 250 + (500 \times 2) = 250 + 1000 = 1250 \]
For \( t = 3 \): \[ g = 250 + (500 \times 3) = 250 + 1500 = 1750 \]
For \( t = 4 \): \[ g = 250 + (500 \times 4) = 250 + 2000 = 2250 \]
For \( t = 5 \): \[ g = 250 + (500 \times 5) = 250 + 2500 = 2750 \]
For \( t = 6 \): \[ g = 250 + (500 \times 6) = 250 + 3000 = 3250 \]
For \( t = 7 \): \[ g = 250 + (500 \times 7) = 250 + 3500 = 3750 \]
For \( t = 8 \): \[ g = 250 + (500 \times 8) = 250 + 4000 = 4250 \]
For \( t = 9 \): \[ g = 250 + (500 \times 9) = 250 + 4500 = 4750 \]
For \( t = 10 \): \[ g = 250 + (500 \times 10) = 250 + 5000 = 5250 \]
Here’s a summary of the gallons in the pool at each hour:
| Time (hours) | Gallons of water in the pool | |--------------|-------------------------------| | 0 | 250 | | 1 | 750 | | 2 | 1250 | | 3 | 1750 | | 4 | 2250 | | 5 | 2750 | | 6 | 3250 | | 7 | 3750 | | 8 | 4250 | | 9 | 4750 | | 10 | 5250 |
This table shows the increase in the amount of water in the pool over the specified time period.