Question

The boiling point of water is 212°F. The boiling point of helium is -452°F. How would you compare the temperatures using an inequality?

Answer 1

To compare the boiling points of water and helium using an inequality, we can express it as follows:

Let \( x \) represent the boiling point of water and \( y \) represent the boiling point of helium. Therefore:

- \( x = 212°F \)
- \( y = -452°F \)

To compare them, we can express this as:

\[
x > y
\]

So it can be stated as:

\[
212°F > -452°F
\]

This indicates that the boiling point of water is greater than the boiling point of helium.