Question

Select all equations that have
as a solution. x=3
A
x+7=10x+7=10x+7=10
B
3+x=33+x=33+x=3
C
x⋅3=1x\cdot 3=1x⋅3=1
D
4⋅x=124\cdot x=124⋅x=12

Answer 1

To determine which of the equations has \( x = 3 \) as a solution, we will substitute \( x = 3 \) into each equation and see if it satisfies them.

**A.** \( x + 7 = 10 \)

Substituting \( x = 3 \):
\[
3 + 7 = 10 \\
10 = 10 \quad \text{(True)}
\]

**B.** \( 3 + x = 3 \)

Substituting \( x = 3 \):
\[
3 + 3 = 3 \\
6 = 3 \quad \text{(False)}
\]

**C.** \( x \cdot 3 = 1 \)

Substituting \( x = 3 \):
\[
3 \cdot 3 = 1 \\
9 = 1 \quad \text{(False)}
\]

**D.** \( 4 \cdot x = 12 \)

Substituting \( x = 3 \):
\[
4 \cdot 3 = 12 \\
12 = 12 \quad \text{(True)}
\]

Thus, the equations that have \( x = 3 \) as a solution are:

- A: \( x + 7 = 10 \)
- D: \( 4 \cdot x = 12 \)