Question

Select all equations that have
as a solution.
A
x+7=10x+7=10x+7=10
B
3+x=33+x=33+x=3
C
x⋅3=1x\cdot 3=1x⋅3=1
D
4⋅x=124\cdot x=124⋅x=12

Answer 1

To determine which equations have \( x = 1 \) as a solution, we will solve each equation for \( x \).

**A.**
\[
x + 7 = 10
\]
Subtracting 7 from both sides:
\[
x = 10 - 7
\]
\[
x = 3
\]
**Conclusion:** \( x = 1 \) is not a solution.

---

**B.**
\[
3 + x = 3
\]
Subtracting 3 from both sides:
\[
x = 3 - 3
\]
\[
x = 0
\]
**Conclusion:** \( x = 1 \) is not a solution.

---

**C.**
\[
x \cdot 3 = 1
\]
Dividing both sides by 3:
\[
x = \frac{1}{3}
\]
**Conclusion:** \( x = 1 \) is not a solution.

---

**D.**
\[
4 \cdot x = 12
\]
Dividing both sides by 4:
\[
x = \frac{12}{4}
\]
\[
x = 3
\]
**Conclusion:** \( x = 1 \) is not a solution.

---

**Final Summary:**
None of the equations (A, B, C, D) have \( x = 1 \) as a solution.