Question
Lead (II) nitrate as Pb(NO3)2 and potassium iodide as KI combine to form the products shown.
2 KNO3 + PbI2
How many moles of each reactant are involved in the reaction?
(1 point)
Responses
2 moles of lead (II) nitrate and 2 moles of potassium iodide
2 moles of lead (II) nitrate and 2 moles of potassium iodide
1 mole of lead (II) nitrate and 2 moles of potassium iodide
1 mole of lead (II) nitrate and 2 moles of potassium iodide
2 moles of lead (II) nitrate and 1 mole of potassium iodide
2 moles of lead (II) nitrate and 1 mole of potassium iodide
1 mole of lead (II) nitrate and 1 mole of potassium iodide
2 KNO3 + PbI2
How many moles of each reactant are involved in the reaction?
(1 point)
Responses
2 moles of lead (II) nitrate and 2 moles of potassium iodide
2 moles of lead (II) nitrate and 2 moles of potassium iodide
1 mole of lead (II) nitrate and 2 moles of potassium iodide
1 mole of lead (II) nitrate and 2 moles of potassium iodide
2 moles of lead (II) nitrate and 1 mole of potassium iodide
2 moles of lead (II) nitrate and 1 mole of potassium iodide
1 mole of lead (II) nitrate and 1 mole of potassium iodide
Answers
GPT-4o mini
To determine the number of moles of each reactant in the reaction between lead (II) nitrate (Pb(NO₃)₂) and potassium iodide (KI), we need to look at the balanced chemical equation:
\[ \text{Pb(NO}_3)_2 + 2 \text{KI} \rightarrow 2 \text{KNO}_3 + \text{PbI}_2 \]
In this balanced equation, we can see that:
- 1 mole of lead (II) nitrate (Pb(NO₃)₂) reacts with 2 moles of potassium iodide (KI).
Based on this, the correct response would be:
**1 mole of lead (II) nitrate and 2 moles of potassium iodide.**
\[ \text{Pb(NO}_3)_2 + 2 \text{KI} \rightarrow 2 \text{KNO}_3 + \text{PbI}_2 \]
In this balanced equation, we can see that:
- 1 mole of lead (II) nitrate (Pb(NO₃)₂) reacts with 2 moles of potassium iodide (KI).
Based on this, the correct response would be:
**1 mole of lead (II) nitrate and 2 moles of potassium iodide.**