The angles of a triangle measure ( x + 10 ), ( x + 20 ), and ( x + 30 ). Find the measure of the smallest angle.

40

50

60

70

1 answer

To find the measure of the smallest angle in the triangle, we start by using the fact that the sum of the angles in a triangle is always \(180^\circ\).

Given the angles:

  1. \(x + 10\)
  2. \(x + 20\)
  3. \(x + 30\)

We can set up the equation: \[ (x + 10) + (x + 20) + (x + 30) = 180 \]

Simplifying this equation: \[ 3x + 60 = 180 \]

Subtract \(60\) from both sides: \[ 3x = 120 \]

Now, divide by \(3\): \[ x = 40 \]

Now we can find the measures of the three angles:

  1. \(x + 10 = 40 + 10 = 50\)
  2. \(x + 20 = 40 + 20 = 60\)
  3. \(x + 30 = 40 + 30 = 70\)

The angles are \(50^\circ\), \(60^\circ\), and \(70^\circ\).

The smallest angle is \(\mathbf{50^\circ}\).