Question
a person applies 98 news of voice to a 20 kg box they applied the force to the box over a 4 mg raising the Box 2 m from the ground how much work is done
Answers
GPT-4o mini
To calculate the work done on the box, we can use the formula for work:
\[
\text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta)
\]
Where:
- \( \text{Force} \) is the applied force,
- \( \text{Distance} \) is the distance moved in the direction of the force, and
- \( \theta \) is the angle between the force and the direction of motion.
In this case, the person applies a force of 98 N (assuming "news of voice" was a typo and you meant Newtons). The box is raised vertically, meaning the angle \( \theta = 0 \) degrees, and \( \cos(0) = 1 \).
The distance the box is raised is 2 meters.
Putting this together:
\[
\text{Work} = 98 \, \text{N} \times 2 \, \text{m} \times \cos(0)
\]
\[
\text{Work} = 98 \, \text{N} \times 2 \, \text{m} \times 1
\]
\[
\text{Work} = 196 \, \text{J}
\]
Therefore, the work done on the box is **196 Joules**.
\[
\text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta)
\]
Where:
- \( \text{Force} \) is the applied force,
- \( \text{Distance} \) is the distance moved in the direction of the force, and
- \( \theta \) is the angle between the force and the direction of motion.
In this case, the person applies a force of 98 N (assuming "news of voice" was a typo and you meant Newtons). The box is raised vertically, meaning the angle \( \theta = 0 \) degrees, and \( \cos(0) = 1 \).
The distance the box is raised is 2 meters.
Putting this together:
\[
\text{Work} = 98 \, \text{N} \times 2 \, \text{m} \times \cos(0)
\]
\[
\text{Work} = 98 \, \text{N} \times 2 \, \text{m} \times 1
\]
\[
\text{Work} = 196 \, \text{J}
\]
Therefore, the work done on the box is **196 Joules**.